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🪨 Free Fall under Gravity

Motion in 1D NEET · JEE · KCET v = u - gt | h = h₀ + ut - ½gt² | v² = u² - 2gΔh
🟢 Object ⬇️ Velocity vector (v) 🏔️ Ground (y = 0) ⚡ g = 9.8 m/s² ↓
g = 9.8 m/s² ↓ | v = u - gt | h = h₀ + ut - ½gt² | v² = u² - 2g(h - h₀)
Height (h)
0.00
m
Velocity (v)
0.00
m/s
Acceleration (a)
-9.80
m/s²
Time to ground
0.00
s

🔋 Energy (mass = 1 kg)

Kinetic Energy (KE)0.00 J
Potential Energy (PE)0.00 J
Total Energy (KE + PE)0.00 J

🔍 What to Observe

  • Acceleration is constant a = -9.8 m/s² throughout motion
  • Velocity increases linearly downward (becomes more negative)
  • Height follows a parabolic curve vs time
  • Total mechanical energy (KE + PE) is constant (no air resistance)
  • At maximum height (if thrown upward), v = 0 but a = -9.8 m/s²
Ready
t = 0.00 s