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📐 Friction on Inclined Plane

Laws of Motion NEET · JEE · KCET f_s ≤ μ_s N | f_k = μ_k N | a = g(sinθ - μ_k cosθ)
🟦 Block ⬇️ mg sinθ ↗️ Normal (N) ⬆️ Friction (f) 🎯 Net Force
N = mg cosθ | f_s_max = μₛN | f_k = μₖN | a = g(sinθ - μₖ cosθ)
Acceleration (a)
0.00
m/s²
Net Force (F_net)
0.00
N
Friction Force (f)
0.00
N
Normal Force (N)
0.00
N

⚡ Forces along the incline

mg sinθ (down) 0.00 N
Friction f (up) 0.00 N
F_net = mg sinθ - f 0.00 N

📊 Motion Status

At Rest
θ_critical = 21.8°

🔍 What to Observe

  • When θ < θ_critical → block stays at rest
  • When θ > θ_critical → block accelerates DOWN
  • Normal force N = mg cosθ decreases as θ increases
  • Friction opposes motion (acts UP the incline)
  • Kinetic friction is constant: f_k = μₖN
  • At θ = 90°, N = 0, block falls freely (a = g)
Ready
Position: 0.00 m from top