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⚙️ Pulley System (Atwood Machine)

Laws of Motion NEET · JEE · KCET a = (m₂ - m₁)g/(m₁ + m₂)
⬆️ m₁ moves UP ⬇️ m₂ moves DOWN 🔵 Mass 1 | 🔴 Mass 2
a = (m₂ - m₁)g/(m₁ + m₂) | T = (2m₁m₂/(m₁ + m₂))g
Acceleration (a)
0.00
m/s²
Tension (T)
0.00
N
Net Force
0.00
N
Velocity (v)
0.00
m/s

⚡ Forces on each mass

m₁: T ↑   m₁g ↓ 0.00 / 0.00 N
m₂: T ↑   m₂g ↓ 0.00 / 0.00 N
F_net = m₂g - m₁g 0.00 N

📊 Motion Direction

m₂ heavier → m₂ moves DOWN

🔍 What to Observe

  • If m₁ = m₂, a = 0 (system at rest or constant speed)
  • If m₂ > m₁, m₂ accelerates DOWN, m₁ accelerates UP
  • Tension is same throughout the string (ideal pulley)
  • Tension is always between m₁g and m₂g
  • Acceleration is less than g unless one mass is zero
Ready
Position: m₁ at top